The Coulomb Electron Speed and Acceleration
in
Bohr’s Model of the Hydrogen Atom
Pavle I. Premović
Laboratory for Geochemistry, Cosmochemistry&Astrochemistry,
University of Niš, pavleipremovic@yahoo.com, Niš, Serbia
FC = keq1q2/R2 … (1)
where ke is
the Coulomb constant (= 8,988 × 109
N m2 C-2)[1],
q1 is the charge of the first object, q 2 is
the charge of another object and R is the distance between these objects.
We will apply the expression (1) in the case of the proton and electron of the hydrogen atom. The proton has a positive charge equal in magnitude to a unit of electron charge e (= 1.60 × 10-19 C). In the ground state of hydrogen atom, its Bohr radius a0 = 5.3 × 10-11 m. The rest mass of electron me = 9.11 × 10-31 kg.
We know in this orbit the electron is exposed to the Coulombic centripetal force: Fp = kee2/R2 and the centrifugal force: Ff = meυn2/R. These two forces are balanced: Fp = Ff or kee2/R2 = meυn2/R. An electron to move one-dimensionally along the straight line towards the proton Fc > Fp or, after some algebra, (meυnR)υn < kee2. Applying Bohr’s quantum condition meυnR = nħ[1], after a bit of algebra, we get
υn < (kee2/ħ) × 1/n.
Let us assume that the electron moves along a straight one-dimensional path in the direction of the proton of hydrogen atom with a final speed equal to υ1 about 2.2 × 106 m sec-1. When this electron reaches the ground state it would orbit the proton in a circle with this speed as in Bohr’s model.
According to Newton’s second law of motion, the acceleration of the electron at R would be equal to the Coulombic force divided by the mass of electron me. This can be represented by the equation
aC = (FC/me) = kee2/meR2 … (2).
By employing eqn. (2), we find that an electron situated at a distance of Bohr’s radius from the proton would reach an acceleration of about 1030 m sec-2. Taking it - as an average acceleration - the electron would reach the speed υ1 for Δt ≈ 2.2 × 10-24 sec.
To get as close to the proton as possible the electron must move at a relativistic speed much higher than υ1 or close to the speed of light c (≈ 3 × 108 m sec-1). The relativistic centrifugal force Ff = meυe2/Rmin /[√(1 - υe2/c2)] has to be equal to the centripetal force Fp = kee2/Rmin. This can be expressed as the equation
or, after some algebra,
Rmin = (kee2/me) × [√(1 – υe2/c2)] × 1/υe2
where Rmin is the smallest distance between the electron approaching the proton with a relativistic speedυe.Solving for Rmin and substituting known values, we getRmin ≈ 2.6 × 10-7 [√(1 – υe2/c2)] × 1/υe2.
The electron is traveling at 99.9999992 % of the speed of light[1] (or υe = 0.999999992c) in the electron
beam of energy as high as 4GeV.[2] Plugging this value for υe after some calculation we find that Rmin
would be about 3.6 × 10-28 m. For comparison, the charge radius of the proton is about 1 × 10-15 m.
Let us denote with ae the average acceleration of the electron approaching to the proton. This acceleration
would be higher than aC and it can be expressed by the following equation
ae = (υe – υ1)/Δt
or
Δt = (υe – υ1)/ae
where Δt is the corresponding time interval. As ae > 1030 m sec-2, we write Δt < (υe – υ1)/1030. Solving
for Δt and substituting the known values we find Δt < 3 × 10-22 sec. Of note, it is generally accepted that
the Planck time tp (≈ 10-43 sec) is the smallest time interval that has a physical meaning. This time interval
is about 1022 times smaller than the smallest time interval measured to date: 10-21 sec.
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